x^2-92x+2100=0

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Solution for x^2-92x+2100=0 equation:



x^2-92x+2100=0
a = 1; b = -92; c = +2100;
Δ = b2-4ac
Δ = -922-4·1·2100
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-8}{2*1}=\frac{84}{2} =42 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+8}{2*1}=\frac{100}{2} =50 $

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